a^2+a-6=-6-5a

Solution for a^2+a-6=-6-5a equation:

a^2+a-6=-6-5a

We move all terms to the left:

a^2+a-6-(-6-5a)=0

We add all the numbers together, and all the variables

a^2+a-(-5a-6)-6=0

We get rid of parentheses

a^2+a+5a+6-6=0

We add all the numbers together, and all the variables

a^2+6a=0

a = 1; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*1}=\frac{-12}{2}
=-6
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*1}=\frac{0}{2}
=0
$